math qn. tough!

• club18

  21 Jun 07, 15:24

  er.. its a level stuff.
  k. here it is..
  
  i) differentiate x^x
  
  ii) hence or otherwise,
  differentiate x^x^x.
  
  help.
  thanks in advance.
• hiphop2009

  21 Jun 07, 15:26

  Originally posted by club18:

  er.. its a level stuff.
  k. here it is..
  
  i) differentiate x^x
  
  ii) hence or otherwise,
  differentiate x^x^x.
  
  help.
  thanks in advance.

  mclaurin series?
• club18

  21 Jun 07, 15:27

  er.. no
• SexyChin

  21 Jun 07, 15:29

  let y = x^x
  
  ln y = xln x
  
  diff w.r.t. x
  
  go figure.
• Diehard_89

  21 Jun 07, 15:29

  y=x^x
  
  ln both side
  
  lny = xlnx
  
  diferentiate both side
  
  (1/y)(dy/dx) = 1 + lnx
  
  make dy/dx the subject
  
  dy/dx = (1+lnx)/(1/y)
• hisoka

  21 Jun 07, 15:30

  Originally posted by club18:

  er.. its a level stuff.
  k. here it is..
  
  i) differentiate x^x
  
  ii) hence or otherwise,
  differentiate x^x^x.
  
  help.
  thanks in advance.

  let y = x^x then take ln both sides. then using chain rule differentiate and solve for dy/dx.
  
  similarly for the other 2
• striderz_o405

  24 Jun 07, 20:28

  my exam ques