In BF3 Boron atom has 6e can we call it an electrophile?
Secondly why LiAlH4 is more reactive than NaBH4 as reducing agent.
Originally posted by hoay:In BF3 Boron atom has 6e can we call it an electrophile?
Secondly why LiAlH4 is more reactive than NaBH4 as reducing agent.
For 2 closely related reasons. Firstly, because Al has a larger atomic radius than B, and thus polarizability of the electron bond pairs of the H- hydride ions increase with increasing distance from the central 'cationic' atom, as predicted by Coloumb's law, and also due to increasing shielding effect from larger number of inner shell electrons. Secondly, the lattice dissociation enthalpy for the covalent bonds with the hydride ions becomes less endothermic (ie. bond weakens) as bond length increases from BH4- to AlH4-, due to less effective overlap of more diffused electron shell orbitals involved in forming the sigma bonds. For both reasons above, concordantly and consequently, LiAlH4 is a significantly more effective delivery agent of H- hydride ion nucleophiles, compared to NaBH4.