H2 Physics P1 ans
-
Hey does anyone know where i can find H2 physics p1 ans? I am not sure if the physics cafe is uploading theirs....
-
Not my subject, of course.
But just to make a suggestion, if no one comes in soon to post their answers, you may like to try this : post your own answers, and ask if anyone have differing answers to discuss/debate those questions.
Better yet, scan and upload your question paper and post the images here, and your chances that some elders (ie. post-A levels pple, eg. private tutors, current undergrads or post grads in this subject) might reply you with their own suggested answers or comments, will be greatly increased.
-
Hi, here are my answers when I was doing the paper, with my rationale for some of the questions. Perhaps we could discuss:
1) B
All points lie close, to the line of best fit, and it has equal distribution of points on both ends of the line.
2) C
3) A
4) D
The key information is that the time starts only when it passes the edge of the cliff.
5) C
Relative speed of approach equals relative speed of seperation, for an elastic collision. It is the only option out of the four that offers this.
6) B
Force = dp/dt = v (dm/dt)
Force = v (vAp)
Force = Apv^2
7) A
Use hydrostatic pressure = hpg (In Formulae List)
8) D
9) C
P = (5) Fv
10) A
11) B
Only tension and weight is involved.
12) D
Most will pick C, because some fail to recognise that 1.2m is the diameter, not the radius.
13) A
14) A
15) D
GPE must rise linearly.
16) C
17) C
Most will choose B, as they did not realised temperature is raised by 1000K, not *to* 1000K.
18) C
19) B
20) B
One trap is that people fail to realised that the wavelength is actually doubled that what is presumed, hence the frequency is 3.3kHz. Draw it out to see.
Another trap is that because the sand seems curved, it looks as if it is transverse. However, take note that it is a sound wave, and sound waves can also form this pattern.
21) D
B is wrong because light incident on the diffraction grating will not affect the angles. The diffraction pattern will just simply shift down.
22) B
23) C
Some will choose D, but they forget that at the third plate, is has the same potential as the second plate, so no work is done from the second plate to the third plate by the electron.
24) B
25) A
Diode, because it's a straight line at sufficiently high voltage.
26) A
27) D
28) A
29) A
30) B
31) A
32) A
Tricky question. But note that it is the *net* amount of charge that they are asking for.
33) B
34) B
Another trick question. The primary coil has *extra* 20 coils, it doesn't increase *to* 20 coils.
35) A
36) C
The electron is trapped in the potential well. Thus, it is guaranteed 100% that you will find the electron in the well. Thus, 1.0.
37) B
38) B
39) C
40) A
Yups, maybe some of my explanations are off... kindly correct me, it's free for debate and discussion! Thanks! =)
-
Do upload the papers :D I could help to solve it and add as a second opinion :) Pm me :D
Thanks!
-
Are you a tuition teacher? I'm only a student who has just taken A level. I would like to share my opinions :). Qn 1: TYS once have this qn, and their answer is A. Qn 7: If it's a cynlider instead of trapesium, the pressure will still be the same? (According to the formula) Qn 20: You meant A instead of B right? Qn 22: Why loudness at P will increase? Qn 25: I understand that the diode has the graph. But for thermistor and LDR, which are semi conductors, if you consider the higher end of the portion, it does look like the graph of forward-biased of the diode. So it can be a thermistor or LDR also. Qn 27: Why is it D? Qn 32: Q = It . So for the negative part of the graph, won't the Charge, Q be -ve as well? Qn 37: Why it isn't A ? Qn 40: Q emit 1 alpha particle, why does it have the same nucleon number? I feel that answer should be D cause R emits all beta particles, thus the nucleon number won't change. Q should have the same proton number also.
-
Originally posted by Chemisfun:
Do upload the papers :D I could help to solve it and add as a second opinion :) Pm me :D
Thanks!
PMed you. -
CaiHongRainx,
Nope I wasn't, but I discussed most of the questions with most of my teachers and received rather similar feedback.
Qn 1: TYS once have this qn, and their answer is A.
Aye brother, if the answer is A in the TYS, then I probably would agree with you then. =)
Qn 7: If it’s a cynlider instead of trapesium, the pressure will still be the same? (According to the formula)Yes. The breadth of the cylinder does not matter. Only the height, density and gravitational pull.
Qn 20: You meant A instead of B right?Yes, thanks for the correction!
Qn 22: Why loudness at P will increase?When the amplitude is reduced, complete cancellation will not occur. Thus, the minimum loudness will thus become louder.
Qn 25: I understand that the diode has the graph. But for thermistor and LDR, which are semi conductors, if you consider the higher end of the portion, it does look like the graph of forward-biased of the diode. So it can be a thermistor or LDR also.For diodes, there is this thing called the saturated current, where there will be a straight line after the 'curve'. Thermistor or LDR does not possess this capability, even at higher ends, because it will still result in an exponential graph.
Diode Graph:
http://www.electronics-for-beginners.com/pictures/diode_graph.PNG
Thermistor (which will be the same for LDR) Graph:
http://www.passmyexams.co.uk/GCSE/physics/images/Graph_for_Thermistor.jpg
This question was a little bit unfair because those who took NTU's H3 Semiconductor Physics and Devices will have an advantage in this.
Qn 27: Why is it D?Area of Q is half of that than that of Area P.
Length of Q is double than that of Area P.
Thus, resistance for Q will be four times than that of P.
Resistance of Q will be 16 Ohm.
Total resistance = 16 + 4 = 20 Ohms, hence D.
Qn 32: Q = It . So for the negative part of the graph, won’t the Charge, Q be -ve as well?Nope it won't, because this is the *net* amount of charge. The net charge will just simply fall, and reach zero.
Qn 37: Why it isn’t A ?To start off, this isn't your fault to think that it is A because Cambridge isn't clear in this question. The shaded portion actually means electrons. At room temperature, the electrons at the donor level will be excited to the conduction band easily (in fact, nearly all of the electrons in the donor level). Thus, there will still be electrons in the conduction band at room temperature.
Qn 40: Q emit 1 alpha particle, why does it have the same nucleon number? I feel that answer should be D cause R emits all beta particles, thus the nucleon number won’t change. Q should have the same proton number alsoMy apologies, I realised I typo hahaha! Yes it is D! =)
-
hi. new here so not really sure what are the rules on posting so just gonna give a shot. admin pls kindly scold if I broke some rules or sth :p
I have questions on qns 35, for h2 physics p1. your answer was A, but I disagree.
(no standard form coz i using internet calculator)
Energy of the electromagnetic radiation is
=0.00000000000000000248625 J
in eV this is
eV
This means that a total of 15.5 eV of radiation is incident on our metal surface of 4.3 eV of work function (pardon english here)
Given einstein's equation here: (in word)
Energy of photons = work function + max KE of photo electrons (Conservation of energy)
therefore max KE of photo electrons = 15.5eV - 4.3 eV = 11.2 eV = 11eV (2.s.f.)
Hence answer should be B.
Help me vet my workings haha. Did I make any careless mistakes along the way?
-
oops. appears to not give any image. okok. here it is painstakingly typed:
E of radiation = (6.63*10^(-34)*3*10^(8))/(80*10^(-9)) =
0.00000000000000000248625 J
in eV this is
0.00000000000000000248625/(1.6*10^(-19)) = 15.5 eV
The rest is given above
